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The quiz is designed for Liquid Solution chapter for JEE Main level.
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Question 1 of 15
1. Question
4 points25 ml of an aqueous solution of KCl was found to require 20 ml of 1 M AgNO3 solution when titrated using a K2CrO4 as indicator. Depression in freezing point of KCl solution with 100% ionization will be
[Kr = 2 K mol-1 kg, and molarity = molality]
(a) 5.00 (b) 3.20 (c) 1.60 (d) 0.80
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Question 2 of 15
2. Question
4 points2.5 gm of a sample having molecular weight 382 was dissolved in 100 gm of water. The freezing point of the solution was -0.490 C. What is the value of Van’t Hoff’s factor for this salt in liquid water? [Kf of H2O is 1.86 Kg mol-1 K.]
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Question 3 of 15
3. Question
4 pointsA real solution will show the positive deviation from Raoult’s law provided
(a) The volume of the solution decreases due to addition of solute
(b) ΔHmix ≠ 0
(c) Solute – solvent interaction (force of attraction) is more than solvent – solvent force of attraction.
(d) Solute – solvent force of attraction is less than solvent – solvent force of attraction
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Question 4 of 15
4. Question
4 pointsIf po and ps are the vapour pressure of solvent and its solution respectively and n1 and n2 are the mole fraction of solvent and solute respectively then which of the following relations is true?
(a) ps = po / n2 (b) po – ps = pon2
(c) ps = pon2 (d) (po – ps) / ps = n1 / (n1 + n2)
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Question 5 of 15
5. Question
4 pointsAn aqueous solution of fructose that will be isotonic with blood at 280 K is [of blood is 6.5 atm at 280 K]
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Question 6 of 15
6. Question
4 pointsAdsorption is accompanied by
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Question 7 of 15
7. Question
4 pointsCalculate the molal elevation constant of water which evaporates at 1000C with absorption of 536 cal/gm
(a) 0.519o (b) 0.612o (c) 0.915o (d) 0.621o
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Question 8 of 15
8. Question
4 pointsAt 40oC the vapour pressures, in torr, of methyl alcohol – ethyl alcohol solutions is represented by the equation; P = 119 XA + 135 where XA is mole-fraction of methyl alcohol, then the value of is
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Question 9 of 15
9. Question
4 pointsFor the given electrolyte AxBy, the degree of dissociation ‘α’ can be given as
(a) (b) i = (1–α) + xα + yα
(c) (d) Either of these
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Question 10 of 15
10. Question
4 pointsThe process of spontaneous adsorption of gas on solid surface is exothermic because
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Question 11 of 15
11. Question
4 pointsNa2SO4 (0·004 M) is isotonic with 0·010 M Glucose. The % dissociation of Na2SO4
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Question 12 of 15
12. Question
4 pointsPhysical adsorbation increases with
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Question 13 of 15
13. Question
4 pointsIn the experiment of depression in freezing point, the equilibrium is estabilized between
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Question 14 of 15
14. Question
4 pointsWhich statement about the composition of the vapour over an ideal 1:1 molar mixture of benzene and toluene is correct? Assume the temperature is constant at 25oC.
Vapour pressure of benzene at 25oC is 75 mm/Hg.
Vapour pressure of toluene at 25oC is 22 mm/Hg.
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Question 15 of 15
15. Question
4 pointsThe vapour pressure of pure benzene at 50oC is 268 torr. How may mol of non – volatile solute per mole of benzene are required to prepare a solution of benzene having a vapour pressure of 167 torr at 50oC.
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